12x^2-72x+88=0

Solution for 12x^2-72x+88=0 equation:

12x^2-72x+88=0

a = 12; b = -72; c = +88;
Δ = b2-4ac
Δ = -722-4·12·88
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8\sqrt{15}}{2*12}=\frac{72-8\sqrt{15}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8\sqrt{15}}{2*12}=\frac{72+8\sqrt{15}}{24}
$